debug()

void debug(mixed object)

The function debug() conveniently shows the project manager the content of a PHP or data variable or a placeholder in debug mode.

• object
  • The ID of a data variable or a placeholder, or
  • A PHP variable (Variables)

Tip: For more information on usage, see Solving Questionnaire Problems.

Important: The function debug() produces output only if the questionnaire was started in debug mode . In the preview () and in regular interviews debug() has no function.

// Display response before the filter for the selection AB01 is executed
debug('AB01');
if (value('AB01') == 2) {
  goToPage('end');
}
 
// Placeholders
$random = random(1,10);
if ($random == 1) {
  replace('%category%', 'employee');
} else {
  replace('%category%', 'superior');
} 
debug('category');
 
// Show PHP variable
$itemlist = getItems('AB09', 'min', 2);
debug($itemlist);